Overview of itertools¶

Let us go through one of the important library to manipulate collections called as itertools.

Functions such as filter and map are part of core Python libraries.
reduce is part of functools.
It is not possible to use these functions to perform advanced operations such as grouped aggregations, joins etc.
Python have several higher level libraries which provide required functionality to perform advanced aggregations such as grouped aggregations, joins etc. itertools is one of the popular library to manipulate collections.

import itertools

itertools?

Type:        module
String form: <module 'itertools' (built-in)>
Docstring:  
Functional tools for creating and using iterators.

Infinite iterators:
count(start=0, step=1) --> start, start+step, start+2*step, ...
cycle(p) --> p0, p1, ... plast, p0, p1, ...
repeat(elem [,n]) --> elem, elem, elem, ... endlessly or up to n times

Iterators terminating on the shortest input sequence:
accumulate(p[, func]) --> p0, p0+p1, p0+p1+p2
chain(p, q, ...) --> p0, p1, ... plast, q0, q1, ... 
chain.from_iterable([p, q, ...]) --> p0, p1, ... plast, q0, q1, ... 
compress(data, selectors) --> (d[0] if s[0]), (d[1] if s[1]), ...
dropwhile(pred, seq) --> seq[n], seq[n+1], starting when pred fails
groupby(iterable[, keyfunc]) --> sub-iterators grouped by value of keyfunc(v)
filterfalse(pred, seq) --> elements of seq where pred(elem) is False
islice(seq, [start,] stop [, step]) --> elements from
       seq[start:stop:step]
starmap(fun, seq) --> fun(*seq[0]), fun(*seq[1]), ...
tee(it, n=2) --> (it1, it2 , ... itn) splits one iterator into n
takewhile(pred, seq) --> seq[0], seq[1], until pred fails
zip_longest(p, q, ...) --> (p[0], q[0]), (p[1], q[1]), ... 

Combinatoric generators:
product(p, q, ... [repeat=1]) --> cartesian product
permutations(p[, r])
combinations(p, r)
combinations_with_replacement(p, r)

Task 1¶

Get cumulative sales from list of transactions.

ns = [1, 2, 3, 4]

import itertools as iter

iter.accumulate?

Init signature: iter.accumulate(self, /, *args, **kwargs)
Docstring:     
accumulate(iterable[, func]) --> accumulate object

Return series of accumulated sums (or other binary function results).
Type:           type
Subclasses:     

list(iter.accumulate(ns))[:10]

[1, 3, 6, 10]

import operator as o
list(iter.accumulate(ns, o.mul))[:10]

[1, 2, 6, 24]

iter.chain?

Init signature: iter.chain(self, /, *args, **kwargs)
Docstring:     
chain(*iterables) --> chain object

Return a chain object whose .__next__() method returns elements from the
first iterable until it is exhausted, then elements from the next
iterable, until all of the iterables are exhausted.
Type:           type
Subclasses:     

l1 = [1, 2, 3, 4]
l2 = [4, 5, 6]

list(iter.chain(l1, l2))

[1, 2, 3, 4, 4, 5, 6]

help(iter.starmap)

Help on class starmap in module itertools:

class starmap(builtins.object)
 |  starmap(function, sequence) --> starmap object
 |  
 |  Return an iterator whose values are returned from the function evaluated
 |  with an argument tuple taken from the given sequence.
 |  
 |  Methods defined here:
 |  
 |  __getattribute__(self, name, /)
 |      Return getattr(self, name).
 |  
 |  __iter__(self, /)
 |      Implement iter(self).
 |  
 |  __new__(*args, **kwargs) from builtins.type
 |      Create and return a new object.  See help(type) for accurate signature.
 |  
 |  __next__(self, /)
 |      Implement next(self).
 |  
 |  __reduce__(...)
 |      Return state information for pickling.

Task - Compute Commission Amount¶

Create a collection with sales and commission percentage. Using that collection compute total commission amount. If the commission percent is None or not present, treat it as 0.

Each element in the collection should be a tuple.
First element is the sales amount and second element is commission percentage.
Commission for each sale can be computed by multiplying commission percentage with sales (make sure to divide commission percentage by 100).
Some of the records does not have commission percentage, in that case commission amount for that sale shall be 0

transactions = [(376.0, 8),
(548.23, 14),
(107.93, 8),
(838.22, 14),
(846.85, 21),
(234.84, None),
(850.2, 21),
(992.2, 21),
(267.01, None),
(958.91, 21),
(412.59, None),
(283.14, None),
(350.01, 14),
(226.95, None),
(132.7, 14)]

iter.starmap(lambda rec: rec[0] * rec[1] if rec[1] else 0, transactions)

<itertools.starmap at 0x7f29b8a12f28>

a = iter.starmap(lambda sale_amount, comm_pct: round(sale_amount * comm_pct, 2) if comm_pct else 0, transactions)

for i in a: print(i)

Mastering Python

Overview of itertools¶

Task 1¶

Task - Compute Commission Amount¶